Respuesta :
The solution to the question is given below.
[tex]\begin{gathered} The\text{ 2.6km is some fraction of the entire Circumference which is: C= 2}\pi r\text{ = 2}\times\text{ }\pi\text{ }\times2.9 \\ \text{ = 5.8}\pi cm \\ \text{ The fraction becomes: }\frac{2.61}{5.8\pi}\text{ = }\frac{0.45}{\pi} \\ \text{The entire circle is: 2 }\pi\text{ radian} \\ \text{ = }\frac{0.45}{\pi}\text{ }\times2\text{ }\times\pi\text{ = 0.9} \\ The\text{ skier has gone 0.9 radian from (-.1.464, 2.503)} \\ \text{The x- cordinate become: =-1.}464\text{ cos}(0.9)\text{ = -1.4625} \\ while\text{ the Y-cordinate becomes: =-1.}464\text{ sin}(0.9)\text{ = -}0.0229 \\ \text{The skier rested at: (-1.4625, -0.0229)} \\ \end{gathered}[/tex]