[tex]\text{volume}=\frac{1}{3}\pi r^2h[/tex]
Therefore let us input the values to find the volume of the cone
[tex]\begin{gathered} \text{volume}=\frac{1}{3}\pi r^2h \\ r=\frac{8}{2}=4\text{ ft} \\ h=9ft \\ \text{volume}=\frac{1}{3}\pi r^2h \\ \text{volume}=\frac{1}{3}\times3.14\times4^2\times^{}9 \\ \text{volume}=\frac{1}{3}\times3.14\times16\times9 \\ \text{volume}=\frac{452.16}{3} \\ \text{volume}=\text{ }150.72ft^2 \end{gathered}[/tex]
The answer should be A.
