In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
Line A:
point 1 (2,7)
point 2 (-1,10)
Line B:
point 1 (-4,7)
point 2 (-1,6)
Line C:
point 1 (6,5)
point 2 (7,9)
Step 02:
perpendicular lines:
slope of the perpendicular line, m’
m' = - 1 / m
Line A:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{10-7}{-1-2}=\frac{3}{-3}=-1[/tex]Line B:
slope:
[tex]m=\frac{y2-y1}{x2-x1}=\frac{6-7}{-1-(-4)}=\frac{-1}{-1+4}=\frac{-1}{3}[/tex]Line C:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{9-5}{7-6}=\frac{4}{1}=4[/tex]m' = - 1 / m ===> none of the slopes meet the condition
The answer is:
there are no perpendicular lines
