Here, we want to find the x and y intercepts of the given line
We start by writing the equation of the line in the standard form
The standard form is;
[tex]y\text{ = mx + b}[/tex]where m is the slope and b is the y-intercept
We have the equation re-written as;
[tex]\begin{gathered} 5y\text{ = 2x - 12} \\ y\text{ = }\frac{2}{5}x\text{ - }\frac{12}{5} \end{gathered}[/tex]As we can see, we have the y-intercept at the point y = -12/5
The coordinate form at this point is (0,-12/5)
To find the x-intercept, we simply set y to zero
This is;
[tex]\begin{gathered} 0\text{ = }\frac{2}{5}x\text{ - }\frac{12}{5} \\ \\ \frac{2}{5}x\text{ = }\frac{12}{5} \\ \\ 2x\text{ = 12} \\ x\text{ = }\frac{12}{2} \\ x\text{ = 6} \end{gathered}[/tex]The x-intercept is thus (6,0)