We will solve as follows:
*First: We identify the pattern, that is:
[tex]\frac{3}{4}-\frac{1}{2}=\frac{1}{4}[/tex][tex]\frac{7}{8}-\frac{3}{4}=\frac{1}{8}[/tex][tex]\frac{15}{16}-\frac{7}{8}=\frac{1}{16}[/tex]From this, we can see tat the pattern follows the rule:
[tex](\frac{1}{2})^{n+1}[/tex]So, the next terms of the sequence will be:
[tex]\frac{15}{16}+(\frac{1}{2})^{4+1}=\frac{31}{32}[/tex]And the next one is:
[tex]\frac{31}{32}+(\frac{1}{2})^{5+1}=\frac{63}{64}[/tex]And those are the next two terms of the sequence.