Given:
[tex]\begin{gathered} y=-x+4----(1) \\ y=-x^2+4----(2) \end{gathered}[/tex]Required:
To find the solutions to the given equations.
Explanation:
Put equation 1 in 2, we get
[tex]\begin{gathered} -x+4=-x^2+4 \\ \\ -x+4+x^2-4=0 \\ \\ x^2-x=0 \\ \\ x(x-1)=0 \\ \\ x=0,1 \end{gathered}[/tex]When x=0,
[tex]\begin{gathered} y=-0+4 \\ y=4 \end{gathered}[/tex]When x=1,
[tex]\begin{gathered} y=-1+4 \\ =3 \end{gathered}[/tex]Final Answer:
The solution are
[tex]x=0,1[/tex]The solution sets are
[tex]\begin{gathered} (0,4)\text{ and} \\ (1,3) \end{gathered}[/tex]