Consider the non-right triangle below.Suppose that m∠CAB=62∘, and that x=35 cm and y=17 cm. What is the area of this triangle? cm^2

Given that:
x=35 cm and y=17 cm
and angle CAB= 62 degree
[tex]\begin{gathered} A=\frac{1}{2}\times x\times y\times\sin (\angle CAB) \\ A=\frac{1}{2}(35)(17)\sin (62) \\ A=297.5\times\sin (62) \\ A=262.67cm^2 \end{gathered}[/tex]