To describe the transfer we will review what the points of the blue and red triangle are.
Blue triangle
I = (-2, 8)
I' = (4, 4)
First, we will determine the x-axis translation
[tex]\begin{gathered} \Delta x=x2-x1 \\ \Delta x=4-(-2) \\ \Delta x=6 \end{gathered}[/tex]
6 units right
Now let's calculate the y-axis transfer
[tex]\begin{gathered} \Delta y=y2-y1 \\ \Delta y=4-8 \\ \Delta y=-4 \end{gathered}[/tex]
4 units down
The answer would be 6 units right and 4 units down
