Answer:
a=1/3, b=-6, c=7
Explanation:
Given the polynomial:
[tex]\frac{1}{3}x^2+7-6x[/tex]We reorder it to rewrite the polynomial in the form ax²+bx+c:
[tex]\frac{1}{3}x^2-6x+7[/tex]Next, by comparing:
• a is the coefficient of x²: a=1/3
,• b is the coefficient of x: b=-6
,• c is the constant: c=7
[tex]a=\frac{1}{3},b=-6,c=7[/tex]