A simple random sample of 800 elements generates a sample proportion overline p =0.66 . ( Round your answers to four decimal places . ) ( a ) Provide a 90 % confidence interval for the population proportion . to ( b ) Provide a 95 % confidence interval for the population proportion . to

A simple random sample of 800 elements generates a sample proportion overline p 066 Round your answers to four decimal places a Provide a 90 confidence interval class=

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STEP - BY - STEP EXPLANATION

Whatto find?

• 90% confidence interval for the population proportion.

,

• 95% confidence interval for the ppulation proportion.

Given:

n= 800

p=0.66

q=1- p= 1- 0.66 =0.34

a) Given a 90% confidence interval,

α =1- 0.90= 0.10

[tex]Z_{\frac{\alpha}{2}}=Z_{\frac{0.10}{2}}=Z_{0.05}=1.645[/tex][tex]C.I=\bar{P}\pm Z_{\frac{\alpha}{2}}\times\sqrt{\frac{\bar{P}\bar{q}}{n}}[/tex][tex]=0.66\pm1.645\times\sqrt{\frac{0.66\times0.34}{800}}[/tex][tex]\begin{gathered} =0.66\pm0.02755 \\ \\ =(0.6324,\text{ 0.6276\rparen} \end{gathered}[/tex]

b)

Given 95% confidence interal.

1- 0.95 =0.

ANSWER

a) (0.6276, 0.6324)