We have the polynomial:
[tex]p^3-216q^3[/tex]We have to factorize it.
We know that 216 is the cube of 6.
We then applied the property for the difference of cubes.
[tex]\begin{gathered} p^3-(6q)^3 \\ (p-6q)(p^2+p\cdot6q+(6q)^2) \\ (p-6q)(p^2+6pq+36q^2) \end{gathered}[/tex]The answer is Option C.
Difference of cubes property:
x^3-y^3 = (x-y)(x^2+xy+y^2)
