Given data
*The given initial volume of water is V_1 = 2 L
*The given initial temperature of the water is T_i = 20 °C
*The given final temperature of the water is T_f = 40 °C
*The coefficient of volumetric expansion of water is
[tex]\alpha=30\times10^{-9}^{}\text{C}[/tex]The formula for the volumetric expansion is given as
[tex]\frac{\Delta V}{V}=\alpha(T_f-T_i)[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \frac{\Delta V}{V_1}=30\times10^{-9}\times(40^0-20^0) \\ V_2-V_1=6\times10^{-7}V_1 \\ V_2=6\times10^{-7}V_1+V_1^{} \\ =V_1(6\times10^{-7}+1) \\ =2.00\text{ L} \end{gathered}[/tex]