We are given a set of coordinates which are;
[tex](-4,-5)[/tex]And the slope which is;
[tex]\frac{1}{2}[/tex]The equation of a line in slope-intercept form is;
[tex]y=mx+b[/tex]Note that in this equation, the variable m is the slope (that is, the coefficient of x). we can now substitute for x, y and m into the equation above and we'll have;
[tex]\begin{gathered} y=mx+b \\ \text{Where,} \\ x=-4,y=-5,m=\frac{1}{2} \\ -5=\frac{1}{2}(-4)+b \\ -5=-2+b \\ \text{Add 2 to both sides of the equation;} \\ -3=b \end{gathered}[/tex]We now have the values of the slope and the y-intercept as
[tex]m=\frac{1}{2},b=-3[/tex]The equation now can be written as;
[tex]\begin{gathered} y=\frac{1}{2}x+(-3) \\ y=\frac{1}{2}x-3 \end{gathered}[/tex]ANSWER:
[tex]\begin{gathered} m=\frac{1}{2} \\ b=-3 \\ \text{Equation;} \\ y=\frac{1}{2}x-3 \end{gathered}[/tex]