Respuesta :

We are given a set of coordinates which are;

[tex](-4,-5)[/tex]

And the slope which is;

[tex]\frac{1}{2}[/tex]

The equation of a line in slope-intercept form is;

[tex]y=mx+b[/tex]

Note that in this equation, the variable m is the slope (that is, the coefficient of x). we can now substitute for x, y and m into the equation above and we'll have;

[tex]\begin{gathered} y=mx+b \\ \text{Where,} \\ x=-4,y=-5,m=\frac{1}{2} \\ -5=\frac{1}{2}(-4)+b \\ -5=-2+b \\ \text{Add 2 to both sides of the equation;} \\ -3=b \end{gathered}[/tex]

We now have the values of the slope and the y-intercept as

[tex]m=\frac{1}{2},b=-3[/tex]

The equation now can be written as;

[tex]\begin{gathered} y=\frac{1}{2}x+(-3) \\ y=\frac{1}{2}x-3 \end{gathered}[/tex]

ANSWER:

[tex]\begin{gathered} m=\frac{1}{2} \\ b=-3 \\ \text{Equation;} \\ y=\frac{1}{2}x-3 \end{gathered}[/tex]