SOLUTION
We want to solve for x in the equation
[tex]14x-\frac{1}{2}\mleft(4x+6\mright)=3\mleft(x-4\mright)-18[/tex]
First we expand the brackets in both sides of the equation, this becomes
[tex]\begin{gathered} 14x-\frac{1}{2}(4x+6)=3(x-4)-18 \\ 14x-2x-3=3x-12-18 \end{gathered}[/tex]
Note that the minus sign multiplies the items in the brackets too
Now, we collect like terms we have
[tex]\begin{gathered} 14x-2x-3x=-12-18+3 \\ 9x=-27 \\ \text{divide both sides by 9, we have } \\ \frac{9x}{9}=\frac{-27}{9} \\ x=-3 \end{gathered}[/tex]
Hence x = -3