The surface area of a pyramid is given as:
[tex]SA=\frac{1}{2}pl+B[/tex]
where p is the perimeter of the base, l is the slant height and B is the area of the base.
In this case the slant height is 4 in.
Now, since the base is a square which sides that has length 5 in. then the perimeter is:
[tex]p=4\cdot5=20[/tex]
The area of the base is the length of the side squared, then we have:
[tex]B=5^2=25[/tex]
Once we know the values we plug them in the formula, then we have:
[tex]\begin{gathered} SA=\frac{1}{2}(20)(4)+25 \\ SA=40+25 \\ SA=65 \end{gathered}[/tex]
Therefore the surface area is 65 squared inches.
