Step 1: Write out the functions
g(x) = { (0.5), (2, 4), (4,6), (5,9), (9,0) }
[tex]h(x)\text{ = }\frac{x\text{ + 8}}{11}[/tex]
Step 2:
For the function g(x),
The inputs variables are: 0 , 2, 4, 5, 9
The outputs variables are: 5, 4, 6, 9, 0
The inverse of an output is its input value.
Therefore,
[tex]g^{-1}(9)\text{ = 5}[/tex]
Step 3: find the inverse of h(x)
To find the inverse of h(x), let y = h(x)
[tex]\begin{gathered} h(x)\text{ = }\frac{x\text{ + 8}}{11} \\ y\text{ = }\frac{x\text{ + 8}}{11} \\ \text{Cross multiply} \\ 11y\text{ = x + 8} \\ \text{Make x subject of formula} \\ 11y\text{ - 8 = x} \\ \text{Therefore, h}^{-1}(x)\text{ = 11x - 8} \\ h^{-1}(x)\text{ = 11x - 8} \end{gathered}[/tex]
Step 4:
[tex]Find(h.h^{-1})(1)[/tex][tex]\begin{gathered} h(x)\text{ = }\frac{x\text{ + 8}}{11} \\ h^{-1}(x)\text{ = 11x - 8} \\ \text{Next, substitute h(x) inverse into h(x).} \\ \text{Therefore} \\ (h.h^{-1})\text{ = }\frac{11x\text{ - 8 + 8}}{11} \\ h.h^{-1}(x)\text{ = x} \\ h.h^{-1}(1)\text{ = 1} \end{gathered}[/tex]
Step 5: Final answer
[tex]\begin{gathered} g^{-1}(9)\text{ = 5} \\ h^{-1}(x)\text{ = 11x - 8} \\ h\lbrack h^{-1}(x)\rbrack\text{ = 1} \end{gathered}[/tex]
