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In the diagram below, GD = 10.1,EF 28.1, and EG 16.9. Find the length==of FC. Round your answer to the nearest tenthif necessary.

In the diagram below GD 101EF 281 and EG 169 Find the lengthof FC Round your answer to the nearest tenthif necessary class=

Respuesta :

Solution:

In the figure;

[tex]\begin{gathered} \frac{EG}{EF}=\frac{ED}{EC} \\ \\ EG=16.9,ED=27,EF=28.1 \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} \frac{16.9}{28.1}=\frac{27}{EC} \\ \\ EC=44.9 \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} FC=EC-EF \\ \\ FC=44.9-28.1 \\ \\ FC=16.8 \end{gathered}[/tex]

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