Respuesta :
We have the following:
Group A:
[tex]\begin{gathered} \bar{x}=\frac{12+14+20+18+15}{5}=\frac{79}{5} \\ \bar{x}=15.8 \end{gathered}[/tex]Group B:
[tex]\begin{gathered} \bar{x}=\frac{13+10+15+9+14}{5}=\frac{61}{5} \\ \bar{x}=12.2 \end{gathered}[/tex]now, the diff value:
[tex]d=\frac{|x_1-x_2|}{\frac{x_1+x_2}{2}}\cdot100_{}[/tex]x1 = 15.8
x2 = 12.2
replacing:
[tex]\begin{gathered} d=\frac{|15.8-12.2_{}|}{\frac{15.8_{}+12.2_{}}{2}}\cdot100_{} \\ d=\frac{3.6}{\frac{28}{2}}\cdot100 \\ d=\frac{3.6}{14}\cdot100 \\ d=0.2571\cdot100 \\ d=25.71 \end{gathered}[/tex]Therefore, the answer is 25.71%
