Given data:
* The equation of the distance traveled by the body in terms of time is,
[tex]d=16t^2[/tex]
Solution:
The distance traveled by the body in time t = 3 s is,
[tex]\begin{gathered} d(3)=16\times(3)^2^{} \\ d(3)=144\text{ ft} \end{gathered}[/tex]
The distance traveled by the body in time t = 3.2 s is,
[tex]\begin{gathered} d(3.2)=16\times3.2^2 \\ d(3.2)=163.84_{}\text{ ft} \end{gathered}[/tex]
Thus, the distance traveled between t = 3 s and t = 3.2 s is,
[tex]\begin{gathered} d(3.2)-d(3)=163.84-144 \\ d(3.2)-d(3)=19.84ft_{} \end{gathered}[/tex]
Thus, the body falls 19.84 ft or approx 20 ft in between 3 s and 3.2 s.
