Respuesta :
the expressions and sums of 3/4?
A)
The given expression is :
[tex]\begin{gathered} \frac{1}{2}+\frac{2}{4} \\ \frac{1}{2}+\frac{2}{4}=\frac{1}{2}+\frac{1}{2} \\ \frac{1}{2}+\frac{2}{4}=\frac{1+1}{2} \\ \frac{1}{2}+\frac{2}{4}=\frac{2}{2} \\ \frac{1}{2}+\frac{2}{4}=1 \end{gathered}[/tex]So, expression A doesnot show the sum or difference of 3/4
B)
The given expression is :
[tex]\begin{gathered} \frac{11}{12}-\frac{1}{6} \\ \text{Take LCM of (12,6) is 12} \\ \frac{11}{12}-\frac{1}{6}=\frac{11-2}{12} \\ \frac{11}{12}-\frac{1}{6}=\frac{9}{12} \\ \frac{11}{12}-\frac{1}{6}=\frac{3}{4} \end{gathered}[/tex]The difference is equal to 3/4
C)
The given expression is ;
[tex]\begin{gathered} \frac{3}{5}+\frac{3}{20} \\ \text{Take LCM of (5 and 20) = 20} \\ \frac{3}{5}+\frac{3}{20}=\frac{12+3}{20} \\ \frac{3}{5}+\frac{3}{20}=\frac{15}{20} \\ \frac{3}{5}+\frac{3}{20}=\frac{3}{4} \end{gathered}[/tex]The sum is equal to 3/4
D)
The given expression is :
[tex]\begin{gathered} \frac{7}{8}-\frac{1}{2} \\ \text{take LCM of (8,2) = 8} \\ \frac{7}{8}-\frac{1}{2}=\frac{7-4}{8} \\ \frac{7}{8}-\frac{1}{2}=\frac{3}{8} \end{gathered}[/tex]The difference is not equal to 3/4
E)
The given expression is :
[tex]\begin{gathered} \frac{2}{3}+\frac{1}{12} \\ \text{take LCM of (3,12) = 12} \\ \frac{2}{3}+\frac{1}{12}=\frac{8+1}{12} \\ \frac{2}{3}+\frac{1}{12}=\frac{9}{12} \\ \frac{2}{3}+\frac{1}{12}=\frac{3}{4} \end{gathered}[/tex]The sum is equal to 3/4
Answer : (B), (C) & (E)
