=O PROBABILITY AND STATISTICSIntroduction to permutations and combinationsSuppose we want to choose 2 colors, without replacement, from the 5 colors red, blue, green, purple, and yellow.(a) How many ways can this be done, if the order of the choices is relevant?0(b) How many ways can this be done, if the order of the choices is not relevant?I need help with this math problem

O PROBABILITY AND STATISTICSIntroduction to permutations and combinationsSuppose we want to choose 2 colors without replacement from the 5 colors red blue green class=

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Answer:

a) 20 ways

b) 10ways

Explanations:

Permuation has to do with arrangement (order matters here) while combination has to do with selection (order of choice does not matter).

a) Suppose we want to choose 2 colors, without replacement, from the 5 colors red, blue, green, purple, and yellow, the number of ways this can be done if the order of the choices is relevant is given as;

[tex]\begin{gathered} 5P_2=\frac{5!}{(5-2)!} \\ 5P_2=\frac{5!}{3!} \\ 5P_2=\frac{5\times4\times3\times2!}{3\times2!} \\ 5P_2=5\times4 \\ 5P_2=20ways \end{gathered}[/tex]

b) If the order of the choices is not relevant, this will be a case of selection (combination rule) as shown:

[tex]\begin{gathered} 5C_2=\frac{5!}{(5-2)!2!} \\ 5C_2=\frac{5!}{3!2!} \\ 5C_2=\frac{5\times4\times3!}{3!\times2!} \\ 5C_2=\frac{5\times4}{2} \\ 5C_2=10ways \end{gathered}[/tex]