A straight wire is carrying a current of 2.0 A. It is placed at an angle of 60 with respect to a magnetic field of strength 0.20 T. if the wire experiences a force of 0.40 N, what is the length wire?

Respuesta :

In order to determine the length of the wire, use the following formula for the force exterded on a wire in a magnetic field:

[tex]F=I\cdot L\cdot B\cdot\sin \theta[/tex]

where,

I: current through the wire = 2.0A

L: length of the wire = ?

B: strength of magnetic field = 0.20T

θ: angle between the axis of the wire and the direction of B = 60 degrees

F: force = 0.40N

Solve the equation above for L, replace the values of the other parameters and simplify:

[tex]\begin{gathered} L=\frac{F}{I\cdot B\cdot\sin \theta} \\ L=\frac{0.40N}{(2.0A)(0.20T)\sin 60} \\ L\approx1.15m \end{gathered}[/tex]

Hence, the length of the wire is approximately 1.15m