The given equation is,
[tex]\begin{gathered} 10x+20=-30+10 \\ \end{gathered}[/tex]On solving we get,
[tex]\begin{gathered} 10x=-20-20 \\ 10x=-40 \\ x=-\frac{40}{10}=-4 \end{gathered}[/tex]Thus the solution is, x = -4.
Thus, we can say that the system has exactly one real solution.
Option c is the correct answer.
