contestada

Rewrite y = a (2)¹/3 in the form y = a(1+r) or y = a(1-r)'. Round each value to the nearest hundredth, if necessary. Then state the growth or decay rate.yoThe rate is about %.This is a rate.

Respuesta :

we have the equation

[tex]y=a(2)^{\frac{t}{3}}[/tex]

Rewrite the given equation

[tex]\begin{gathered} y=a(2^{\frac{1}{3}})^t \\ y=a(1.26)^t \\ y=a(1+0.26)^t \end{gathered}[/tex]

the base of the exponential function is b=1.26

1.26 > 1

that means

is an exponential growth function

1+r=1.26

r=1.26-1

r=0.26

therefore

The rate is about 26%

This is a growth rate

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