Find the volume of the cone, use 3 for π

Given:
Cone with diameter of 14 ft, and height of 4 ft.
First, determine the radius of the cone, by dividing the diameter by 2.
[tex]\begin{gathered} r=\frac{d}{2} \\ r=\frac{14\text{ ft}}{2} \\ r=7\text{ ft} \end{gathered}[/tex]Now that we have the radius, substitute π = 3, r = 7 ft, and h = 4 ft to the formula of the volume of the cone.
[tex]\begin{gathered} V=\frac{\pi r^2h}{3} \\ V=\frac{(3)(7\text{ ft})^2(4\text{ ft})}{3} \\ V=\frac{3(49\text{ ft}^2)(4\text{ ft})}{3} \\ V=\frac{588\text{ ft}^3}{3} \\ V=196\text{ ft}^3 \\ \\ \text{Therefore, the volume of the cone is }196\text{ ft}^3. \end{gathered}[/tex]