Respuesta :
Answer:
16.12 hours
Explanation:
A continuous exponential growth model is given below:
[tex]P(t)=P_oe^{rt}[/tex]• The growth rate, r = 4.3% = 0.043
,• t = time in hours
,• Po = Initial population
,• P(t) = Present population
We want to find the number of hours it takes the population to double. That is if the initial population, Po = 1
• The present population, P(t) = 1 x 2 = 2.
Substitute these values into the model above to get:
[tex]2=1(e^{0.043t})[/tex]Since natural logarithm(ln) is the inverse of exponential, take the natural logarithm of both sides to remove the exponential operator.
[tex]\begin{gathered} \ln (2)=\ln (e^{0.043t}) \\ \ln (2)=0.043t \end{gathered}[/tex]Divide both sides by 0.043.
[tex]\begin{gathered} \frac{\ln (2)}{0.043}=\frac{0.043t}{0.043} \\ t=\frac{\ln(2)}{0.043} \\ t\approx16.12 \end{gathered}[/tex]It will take 16.12 hours for the size of the sample to double.
