Answer
Mg(OH)2 is the limiting reactant
Mass of MgCl2 produced = 3.02 g
Explanation
Given: The balanced chemical equation
mass of Mg(OH)2 = 1.85 g
mass of HCl = 3.71
Solution
Mg(OH)2
[tex]1.85g\text{ Mg\lparen OH\rparen}_2\text{ x }\frac{1\text{ mol Mg\lparen OH\rparen}_2}{58,3197g}\text{ x }\frac{1\text{ MgCl}_2}{1\text{ Mg\lparen OH\rparen}_2}\text{ = 0.031 mol MgCl}_2[/tex]HCl
[tex]3.71g\text{ HCl x }\frac{1\text{ mol HCl}}{36,458g}\text{ x }\frac{1\text{ MgCl}_2}{2\text{ HCl}}\text{ = 0.051 mol MgCl}_2[/tex]Therefore Mg(OH)2 is the limiting reactant.
Calculation of MgCl2 mass
[tex]0.031\text{ mol MgCl}_2\text{ x }\frac{95,211g}{1\text{ mol MgCl}_2}\text{ = 3.02 g}[/tex]