I would appreciate the help on this problem. Three consecutive odd numbered lockers sum 711. What is the first locker in the group?

235
1) Three consecutive odd numbers can be represented as
n +n+2 +n+4
2) So we can write the following since their sum is 711
n +n+2 +n+4 = 711 Combine like terms
3n+6=711 subtract 8from both sides
3n= 705
n=235
Let's plug into the formula 2n +1 to find the first locker:
So the first locker is 235