Given:
The mass of the object, m=4.85 kg
The position of the object is given by the equation,
[tex]x=(3.75\text{ m})\cos(6.12\pi t)\text{ }\rightarrow\text{ \lparen i\rparen}[/tex]
The angular frequency, ω=19.2 rad/s
The frequency, f=3.03 Hz
The period, T=0.33 s
To find:
(d) Spring constants.
Explanation:
The spring constant of a spring is related to the angular frequency of the oscillation of the spring by the equation,
[tex]\omega=\sqrt{\frac{k}{m}}[/tex]
Where k is the spring constant.
On substituting the known values,
[tex]\begin{gathered} 19.2=\sqrt{\frac{k}{4.85}} \\ \Rightarrow k=19.2^2\times4.85 \\ =1787.9\text{ N/m} \end{gathered}[/tex]
Final answer:
The spring constant of the spring is 1787.9 N/m
