Given the function:
[tex]y=\cot (x+\frac{\pi}{6})[/tex]
Let's graph the function.
Apply the form:
[tex]y=a\cot (bx-c)+d[/tex]
Thus, we have the values:
a = 1
b = 1
c = - π/6
d = 0
Here, the graph does not have a minimum of maximum value, hence there is no amplitude.
To find the period, we have:
[tex]period=\frac{\pi}{|b|}=\frac{\pi}{1}=\pi[/tex]
For the phase shift, we have:
[tex]\frac{c}{b}=\frac{-\frac{\pi}{6}}{1}=-\frac{\pi}{6}[/tex]
Therefore, the graph of the function is:
