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If a mixture of Ne and Ar has a total pressure of 1.5 atm at 296 K in a 0.5 L container, what is the partial pressure of Ne if Ne is present in a mole fraction of 0.34?

Respuesta :

To answer this question, we have to use the partial pressures gas law, that states that:

[tex]P_i=X_iP_T[/tex]

Where Pi is the partial pressure of the gas, Xi is the mole fraction of the gas and PT is the total pressure, replace for the given values:

[tex]\begin{gathered} P_i=0.34\cdot1.5atm \\ P_i=0.51atm \end{gathered}[/tex]

It means that the partial pressure of Ne is 0.51atm.

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