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Problem Print Ama groundhog really? Well, no but I've always felt a connection to Punxsulawney Phil because my birthday is on February 2nd, the same day folks watch to see if Punxsutawney Phil sees his siadow!! had fun connecting what I know about geometry to use my height, Phil's height and my shadow length to find what the length of Phil's shadow would be at the same time of day Here's the information I used • Phil's height = 51.2 cm • Suzanne's height = 5'4" • Suzanne's shadow length at Gobbler's Knob = 762 cm 34" 51.2 em 76.2cm Question: What did I find as the length of Phil's shadow?

Respuesta :

First, we need to convert Suzanne's height to centimeters. That is

[tex]\begin{gathered} 5\text{feet and 4 inches is equal to } \\ 5\text{ fe}ets=152.4\operatorname{cm} \\ 4\text{ inches=}10.16\operatorname{cm} \end{gathered}[/tex]

so, 5feets and 4 inches are equal to 162.56cm. Now, we can draw a picture of our problem:

where x is Phil's shadow, Since both triangles are similar, then the following ratios must be preserved:

[tex]\frac{x}{76.2}=\frac{51.2}{162.56}[/tex]

Then, x is given by

[tex]x=76.2\times\frac{51.2}{162.56}[/tex]

which gives

[tex]x=24\operatorname{cm}[/tex]

Then, Phil's shadow measure 24 centimeters.

Ver imagen ChantelleC160864

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