For function one, when we have the linear equation:
[tex]y=mx+b[/tex]
The unit rate will be the "m" value, here we have
[tex]y=\frac{1}{4}x+2[/tex]
Then
[tex]m=\frac{1}{4}[/tex]
That's the unit rate for function one
To find out the unit rate for function two, we must take two points of the graphic, in a generical way they're are
[tex]\begin{gathered} A=(x_a,y_a) \\ B=(x_b,y_b)_{} \end{gathered}[/tex]
The unit rate will be
[tex]m=\frac{y_b-y_a}{x_b-x_a_{}}[/tex]
I'll use the points
[tex]\begin{gathered} A=(3,3) \\ B=(0,1) \end{gathered}[/tex]
Then the unit rate will be
[tex]m=\frac{1-3}{0-(-3)}=\frac{2}{3}[/tex]
Hence the unit rate for function two is m = 2/3
