Answer:
[tex]273\text{ mmHg}[/tex]Explanation:
Here, we want to get the pressure in mmHg
Using the ideal gas equation:
[tex]\begin{gathered} PV\text{ = nRT} \\ P\text{ = }\frac{nRT}{V} \end{gathered}[/tex]Where:
P is the pressure in atm which we want to calculate (we would convert to mmHg after calculation)
n is the number of moles which is 0.025 mole
T is the temperature in Kelvin which is 350K
V is the volume which is 2L
R is the molar gas constant which is 0.0821 L.atm/mol.K
Substituting the values, we have it that:
[tex]\begin{gathered} P\text{ = }\frac{0.025\times0.0821\times350}{2} \\ \\ P\text{ = 0.36 atm} \end{gathered}[/tex]Finally, we have to convert this to mmHg
Mathematically:
[tex]\begin{gathered} 1\text{ atm = 760 mmHg} \\ 0.36\text{ atm = 0.36 }\times\text{ 760} \\ =\text{ 273 mmHg} \end{gathered}[/tex]