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You create a solution for a lab, in which you weigh 0. 81 g of nacl and dissolve it in water. The volume of the resulting aqueous nacl solution is 12. 2 ml. Assuming the molar mass of nacl is 58. 443 g/mol, how many moles of nacl did you use?.

Respuesta :

0.01385 moles of NACL are present in a solution of 0. 81 g of NACL dissolved in water. The final aqueous nacl solution has a volume of 12.2 ml. assuming a molar mass of 58. 443 g/mole for nacl.

A three-dimensional space's occupied volume is measured. It is frequently measured numerically with SI-derived units (such the cubic metre and litre) or with other imperial units (such as the gallon, quart, cubic inch). Volume and length are related in how they are defined (cubed).

Mass of NACL = 0.81g

Molar mass of NACL= 58.443 g/mole

Mole of NACL = Mass of NACL/Molar mass of NACL

                         = 0.81g/58.443

Moles of NACL= 0.01385 mole

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