in the following, write an algebraic expression in terms of the given variables that represent the indicated quantity....The amount of bacteria after N min, if the initial amount of bacteria is Q and the amount of bacteria triples every 20 sec. (Hint: the answer should contain q as well as n).

Respuesta :

Let q be the amount of bacteria after n minutes. We know that the amount of bateria triples every 20 seconds, this means that in one minute the amount of bacteria will triples 3 times, that is the amount triples every:

[tex]\frac{1}{3\text{ }}\text{ min}[/tex]

The expression we are looking for has to be of the form:

[tex]q(n)=Q(3^{kn})[/tex]

So we need to find the coefficient k. To do this we know that after 1/3 of a minute the amount will be 3Q, then we have:

[tex]\begin{gathered} q(1)=Q(3^{\frac{1}{3}k}) \\ 3Q=Q(3^{\frac{1}{3}k}) \\ 3=3^{\frac{1}{3}k} \\ \text{which implies that:} \\ \frac{1}{3}k=1 \\ k=3 \end{gathered}[/tex]

Therefore the equation we are lokking for is:

[tex]q(n)=Q^{}(3^{3n})[/tex]