f(x) = x² + 5
find the axis of symmetry and vertex
find the domain and range.
If we write the parable equation in this form: y = a(x - h)² + k then the vertex is (h, k)
In this case: y = 1(x - 0)² + 5, then the vertex is (0, 5)
Since it is a parable that opens up and its vertex is on y axis (because x of the vertex is 0) then the axis of symmetry is the y axis or x = 0
Domain is all the values that x can take, in this case, x can take any real number, so the domain is (-inf, inf)
Range is all the values the y can take, in this case it can take value from 5 to inf, so the range is [5, inf)
