Answer:[tex]y\text{ - 2 = }\frac{-1}{3}(x\text{ + 3)}[/tex]Explanations:
The point - slope form of the equation of a line is given as:
[tex]y-y_1=m(x-x_1)[/tex]
m represents the slope of the line and is given as:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]
The slope of the line passing through the points (-3, 2) and (9, -2) is:
[tex]\begin{gathered} m\text{ = }\frac{-2-2}{9-(-3)} \\ m\text{ = }\frac{-4}{12} \\ m\text{ = }\frac{-1}{3} \end{gathered}[/tex]
The equation of the line considering the point (-3, 2) is therefore:
[tex]\begin{gathered} y\text{ - 2 = }\frac{-1}{3}(x\text{ - }(-3)\text{ )} \\ y\text{ - 2 = }\frac{-1}{3}(x\text{ + 3)} \end{gathered}[/tex]
