on5x - 1 < 19
To solve this inequality add 1 to both sides
[tex]\begin{gathered} 5x-1+1<19+1 \\ 5x<20 \end{gathered}[/tex]Now divide both sides by 5
[tex]\begin{gathered} \frac{5x}{5}<\frac{20}{5} \\ x<4 \end{gathered}[/tex]The solutions lie in the area left to the number 4
For the second inequality
[tex]-3-x+1\leq1[/tex]Add first we will add the like terms in the left side
[tex]\begin{gathered} (-3+1)-x\leq1 \\ -2-x\leq1 \end{gathered}[/tex]Now add 2 for both sides
[tex]\begin{gathered} -2+2-x\leq1+2 \\ -x\leq3 \end{gathered}[/tex]We need to divide both sides by -1, but we should reverse the sign of inequality
[tex]\begin{gathered} \frac{-x}{-1}\ge\frac{3}{-1} \\ x\ge-3 \end{gathered}[/tex]We reversed the sign of inequality when divides it by -ve number
Since 2 < 3
Then if we divide both sides by -1, then it will be
-2 < -3 which is wrong -2 greater than -3, then we should reverse the sign of inequality if we multiply or divide it by a negative number
Then the solutions of the 2nd inequality lie right to -3
Let us draw them
The red part is the solution to the 1st inequality
The blue par is the solution to the 2nd inequality
The area with the 2 colors is the area of the common solution of both inequalities
