Answer:
a = -493.83 m/s²
Explanation:
The acceleration can be calculated as:
[tex]a=\frac{v_f-v_i}{t}[/tex]
Where vf is the final velocity, vi is the initial velocity and t is the time.
Then, we need to convert 320 km/h to m/s as follows:
[tex]320\frac{\operatorname{km}}{h}\times\frac{1000m}{1\operatorname{km}}\times\frac{1h}{3600s}=88.89\text{ m/s}[/tex]
Now, we can replace vf by 0 m/s, vi by 88.89 m/s, and t by 0.18 s to get an acceleration equal to:
[tex]\begin{gathered} a=\frac{0-88.89\text{ m/s}}{0.18s}=\frac{-88.89\text{ m/s}}{0.18s}=-493.83m/s^2 \\ \end{gathered}[/tex]
Therefore, the acceleration that takes place in this time is equal to -493.83 m/s²
