[tex]D)17,15,13,11[/tex]
Explanation
Step 1
we have the recursive formula
[tex]f(x)=\begin{cases}f(1)=17 \\ f(n)=f(n-1)-2\text{ if n }>1\end{cases}[/tex]
A recursive formula is a formula that defines each term of a sequence using the preceding term(s), we can see in the formula that the new term ( f(n)) equals the previous term minus 2
so
[tex]\begin{gathered} f(1)=17 \\ hence \\ f(n)=f(n-1)-2 \\ \text{for n=2} \\ f(2)=f(2-1)-2 \\ f(2)=f(1)-2 \\ f(2)=17-2=15 \\ so,\text{ the second term is 15} \end{gathered}[/tex]
and so on,
Now for n=3
[tex]\begin{gathered} f(n)=f(n-1)-2 \\ f(3)=f(3-1)-2 \\ f(3)=f(2)-2 \\ f(3)=15-2=13 \\ so,the\text{ second third terms i s13} \end{gathered}[/tex]
for n=4
[tex]\begin{gathered} f(n)=f(n-1)-2 \\ f(4)=f(4-1)-2 \\ f(4)=f(3)-2 \\ f(4)=13-2=11 \\ \text{hence, the fourth term is 11} \end{gathered}[/tex]
so, the answer is
D) 17,15,13,11
I hope this helps you
