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Suppose the population of a small town increases from 12,334 to 16,049. What is the percentincrease in the population, rounded to the nearest tenth of a percent?

Respuesta :

First, we compute the population increase:

[tex]16049-12334=3715.[/tex]

Now we divided the above result by the initial population:

[tex]\frac{3715}{16049}\approx0.23147.[/tex]

Finally, we multiply by 100 and round to the nearest tenth of percent:

[tex]100\cdot0.23147=23.147\approx23.1.[/tex]

Answer: 23.1%

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