Answer:
Outer cylinder: 2939.0 cm³
Inner cylinder: 360.0 cm³
Unused roll: 2579.0 cm³
Explanation:
The volume of a cylinder can be calculated as
[tex]V=\pi r^2h[/tex]
Where π = 3.14, r is the radius and h is the height.
For the outer cylinder, the diameter is 12 cm, so the radius is
r = 12 cm/2 = 6 cm
Then, the volume of the cylinder is
[tex]\begin{gathered} V=(3.14)(6\text{ cm\rparen}^2(26\text{ cm\rparen} \\ V=2939.0\text{ cm}^3 \end{gathered}[/tex]
For the inner cylinder, the diameter is 4.2 cm, so the radius and its volume is
r = 4.2 cm/2 = 2.1 cm
[tex]\begin{gathered} V=3.14(2.1\text{ cm\rparen}^2(26\text{ cm\rparen} \\ V=360.0\text{ cm}^3 \end{gathered}[/tex]
Finally, the volume of the unused roll is the difference between the outer and the inner cylinders, so
2939.0 cm³ - 360.0 cm³ = 2579.0 cm³
So, the answers are
Outer cylinder: 2939.0 cm³
Inner cylinder: 360.0 cm³
Unused roll: 2579.0 cm³
