Circle O has diameter FG and chord FH. Calculate the measure of < HFG if GH = 72°

Given the figure in the attached image.
Circle O has diameter FG and chord FH.
If arc GH is;
[tex]GH=72^{\circ}[/tex]we want to find the measure of angle HFG.
Recall that from circle geometry theorems;
"The angle at the center of a circle is twice the angle at the circumference of the circle."
So;
[tex]\begin{gathered} 2\times m\measuredangle HFG=m\measuredangle GOH \\ m\measuredangle HFG=\frac{1}{2}m\measuredangle GOH \\ m\measuredangle HFG=\frac{1}{2}GH \end{gathered}[/tex]substituting the value of GH;
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