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Colton is flying a kite, holding his hands a distance of 3 feet above the ground and
letting all the kite's string play out. He measures the angle of elevation from his hand
to the kite to be 32°. If the string from the kite to his hand is 90 feet long, how many
feet is the kite above the ground? Round your answer to the nearest hundredth of a
foot if necessary.

Respuesta :

The height of the kite above the ground is; approximately 50.69 feet.

What are trigonometric identities?

Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.

The height of his hands above the ground, h is given by 3 feet

Angle of elevation of the string (above the horizontal), θ = 32°

Length of the string, l is given as 90 feet

The height of the kite above the ground is given by trigonometric ratios as ;

Sin∅ =h /90

Sin 32°= h/90

0.52 =h /90 (Sin32°= 0.52)

so h= 47.69 feet

Then height from ground is (H) = 3 +47.69  

H = 50.69 feet

The height of the kite above the ground ,  ≈ 50.69 feet

Learn more about trigonometric ratios here:

brainly.com/question/9085166

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