We are asked to determine the mass of 19 gallons of gasoline. To do that we will use the following formula:
[tex]m=\rho V[/tex]Where:
[tex]\begin{gathered} m=\text{ mass} \\ \rho=\text{ density} \\ V=\text{ Volume} \end{gathered}[/tex]First, we will convert the slug to pounds using the following conversion factor:
[tex]1\text{ slug }=32.174\text{ pounds}[/tex]Multiplying by the conversion factor we get:
[tex]1.32\frac{slug}{ft^3}\times\frac{32.174lb}{1slug}=42.47\frac{lb}{ft^3}[/tex]Now, we will convert the gallons into cubic feet using the following conversion factor:
[tex]1\text{ gal}=1.161ft{}^3[/tex]Multiplying by the conversion factor:
[tex]19gal\times\frac{1.161ft^3}{1gal}=22.06ft^3[/tex]Now, we substitute in the formula for the mass:
[tex]m=(42.47\frac{lb}{ft^3})(22.06ft^3)[/tex]Solving the operations:
[tex]m=936.8882lb[/tex]Therefore, the mass is 936.8882 pounds.
