A sock drawer has three colors of socks: white, brown, and black
The probability of getting a black sock = 7/12
The probability of getting a white sock = 1/4
The probability of getting a brown sock = ?
Recall that the sum of all probabilities must be equal to 1
So, we can write
[tex]P(white)+P(black)+P(brown)=1[/tex]
Substitute the given probabilities and solve for P(brown)
[tex]\begin{gathered} P(white)+P(black)+P(brown)=1 \\ \frac{1}{4}+\frac{7}{12}+P(brown)=1 \\ P(brown)=1-\frac{1}{4}-\frac{7}{12} \\ P(brown)=\frac{1}{6} \end{gathered}[/tex]
Therefore, the probability of getting a brown sock is 1/6
Option D is the correct answer.
