Given:
If the sum of the first two of the five consecutive odd integers is 52.
The five consecutive odd integers are,
[tex]x,x+2,x+4,x+6,x+8[/tex]The sum of first two consecutive odd integers is 52.
[tex]\begin{gathered} x+x+2=52 \\ 2x+2=52 \\ 2x=52-2 \\ 2x=50 \\ x=\frac{50}{2} \\ x=25 \end{gathered}[/tex]The five odd integers are,
[tex]\begin{gathered} x=25 \\ x+2=25+2=27 \\ x+4=25+4=29 \\ x+6=25+6=31 \\ x+8=25+8=33 \end{gathered}[/tex]Now, the sum of last two integers is,
[tex]31+33=64[/tex]The sum of the last two integers is 64
