Solution
we have the following equation:
[tex]A=A_pe^{-0.0099x}[/tex]For this case we can do this:
[tex]0.3A_p=A_pe^{-0.0099x}[/tex]We can cancel in both sides Ap and then we can apply natural log and we got:
[tex]\ln (0.3)=-0.0099x[/tex]Solving for x who represent t we got:
[tex]x=\frac{\ln (0.3)}{-0.0099}=121.61[/tex]Rounded to the nearest year we got:
121yr