Given:
Number of orange marbles = 4
Number of blue marbles = 6
Number of red marbles = 8
Number of green marbles = 7
Number of white marbles = 2
Required: Probability of choosing orange marble then white marble
Explanation:
Total number of marbles
[tex]\begin{gathered} =4+6+8+7+2 \\ =27 \end{gathered}[/tex]Probability of choosing first marble as orange marble =
[tex]\begin{gathered} =\frac{\text{ Number of orange marbles}}{\text{ Total number of marbles}} \\ =\frac{4}{27} \end{gathered}[/tex]After selecting the first marble, the total number of marbles remaining is 27 - 1 = 26.
Probability of choosing a white marble as the second marble
[tex]\begin{gathered} =\frac{\text{ Number of white marbles }}{\text{ Total number of marbles remaining}} \\ =\frac{2}{26} \end{gathered}[/tex]So, P(Orange, then white)
[tex]\begin{gathered} =\frac{4}{27}\cdot\frac{2}{26} \\ =\frac{8}{702} \end{gathered}[/tex]Final Answer: P(Orange, then white) = 8/702
